∫0xxsin(x-t)2dt=________.

admin2018-05-23  16

问题 0xxsin(x-t)2dt=________.

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答案2sinx2+2x2cosx2

解析0xxsin(x一t)2dt=x∫0xsin(x一t)dtx∫x0sinμ2(—dμ)=x∫0xsinμ2dμ,
原式=(x∫0xsinμ2dμ)’’=(∫0xsinμ2dμ+xsinx2)=2sinx2+2x2cosx2.   
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