设(ay-2xy2)dx+(bx2y+4x+3)dy为某个二元函数的全微分,则a=_______,b=_______.

admin2018-05-21  26

问题 设(ay-2xy2)dx+(bx2y+4x+3)dy为某个二元函数的全微分,则a=_______,b=_______.

选项

答案4,-2

解析 令P(x,y)=ay-2xy2,Q(x,y)=bx2y+4x+3,
因为(ay-2xy2)dx+(bx2y+4x+3)dy为某个二元函数的全微分,

=a-4xy,于是a=4,b=-2.
转载请注明原文地址:https://jikaoti.com/ti/pMVRFFFM
0

最新回复(0)