曲线ex+y-sin(xy)=e在点(0,1)处的切线为________.

admin2021-10-18  24

问题 曲线ex+y-sin(xy)=e在点(0,1)处的切线为________.

选项

答案y=(1/e-1)x+1

解析 ex+y-sin(xy)=e两边对x求导得ex+y(1+dy/dx)-cos(xy)(y+xdy/dx)=0,将x=0,y=1代入上式得dy/dx|x=0=1/e-1,故切线方程为y-1=(1/e-1)x,或y=(1/e-1)x+1.
转载请注明原文地址:https://jikaoti.com/ti/RWlRFFFM
0

最新回复(0)