求∫sinx/(sinx-cosx)dx.

admin2021-10-18  38

问题 求∫sinx/(sinx-cosx)dx.

选项

答案∫sinx/(sinx-cosx)dx=1/2∫sin[(x-π/4)+π/4]/sin(x-π/4)dx=1/2∫[sin(x-π/4)+cos(x-π/4)]/sin(x-π/4)dx=x/2+1/2ln|sin(x-π/4)|+C.

解析
转载请注明原文地址:https://jikaoti.com/ti/AllRFFFM
0

最新回复(0)