求下列函数的偏导数(或全导数): z=(x+2y)2x+y;

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问题 求下列函数的偏导数(或全导数):
z=(x+2y)2x+y

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答案设u=x+2y,v=2x+y,z=uv,则 [*]=vuv-1+2uvlnu =(2x+y)(x+2y)2x+y-1+2(x+2y)2x+yln(x+2y), [*]=2vuv-1+uvlnu =2(2x+y)(x+2y)2x+y-1+(x+2y)2x+yln(x+2y).

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