独立投骰子两次,X,Y表示投出的点数,令A={X+Y=10},B={X>Y},则P(A+B)=________.

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问题 独立投骰子两次,X,Y表示投出的点数,令A={X+Y=10},B={X>Y},则P(A+B)=________.

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答案[*]

解析 P(A)=P{X=4,Y=6}+P{X=5,Y=5)+P{X=6,Y=4}=3×1/36=1/12,
P(B)=P{X=2,Y=1}+P{X=3,Y=1)+P{X=3,Y=2}+P{X=4,Y=3}
+P{X=4,Y=2}+P(X=4,Y=1}+P{X=5,Y=4}+P{X=5,Y=3}
+P{X=5,Y=2}+P{X=5,Y=1}+P{X=6,Y=5}+P{X=6,Y=4}
+P{X=6,Y=3}+P{X=6,Y=2)+P{X=6,Y=1}=15/36=5/12,
P(AB)=P{X=6,Y=4}=1/36,
则P(A+B)=P(A)+P(B)-P(AB)=1/12+5/12-1/36=17/36.
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