设函数z=f(x,y)(xy≠0)满足f(xy,)=y2(x2-1),则dz=_______.

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问题 设函数z=f(x,y)(xy≠0)满足f(xy,)=y2(x2-1),则dz=_______.

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答案(2x-y)dx-xdy

解析 设xy=u,=v,有x2,y2=uv.则
f(u,v)=uv=u2-uv,即z=f(x,y)=x2-xy.
所以dz=(2x-y)dx-xdy.
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