设函数y=y(x)由e2x+y-cosxy=e-1确定,则曲线y=y(x)在x=0对应点处的法线方程为__________.

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问题 设函数y=y(x)由e2x+y-cosxy=e-1确定,则曲线y=y(x)在x=0对应点处的法线方程为__________.

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答案y=1/2x+1

解析 当x=0时,y=1,
    e2x+y-cosxy=e-1两边对x求导得+sin(xy)
    将x=0,y=1代入得
    故所求法线方程为y-1=1/2(x-0),即y=1/2x+1.
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