设f(u)连续,则∫0xdu∫u1vf(u2-v2)dv=______.

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问题 设f(u)连续,则0xdu∫u1vf(u2-v2)dv=______.

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答案-xf(x2-1)

解析u1vf(u2-v2)dv=u1f(u2-v2)d(u2-v2)=f(t)dt,
0xvf(u2-v2)dv=0xdu∫0u2-1f(t)dt=f(t)dt,
0xdu∫u1(u2-v2)dv=-xf(x2-1).
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