首页
外语
计算机
考研
公务员
职业资格
财经
工程
司法
医学
专升本
自考
实用职业技能
登录
财经
Due to popular demand by the staff members, the scheduled talk by Mr. Smith will take place______Room 15 instead of Room 20 as w
Due to popular demand by the staff members, the scheduled talk by Mr. Smith will take place______Room 15 instead of Room 20 as w
admin
2015-05-09
38
问题
Due to popular demand by the staff members, the scheduled talk by Mr. Smith will take place______Room 15 instead of Room 20 as was first planned.
选项
A、in
B、on
C、of
D、as
答案
A
解析
由于员工的普遍要求,史密斯先生原定在15号房间进行的演讲将在20号房间进行。本题需选择适当的介词"in",故选A。
转载请注明原文地址:https://jikaoti.com/ti/sh2QFFFM
本试题收录于:
英语题库银行系统招聘考试分类
0
英语
银行系统招聘考试
相关试题推荐
GovernorOgden’sneweconomicpolicieswillfocuson__________morejobsinPaxtonCounty.
Ifsustainablecompetitiveadvantagedependsonwork-forceskills.Americanfirmshaveaproblem.Human-resourcemanagementisno
Ingeneral,oursocietyisbecomingoneofgiantenterprisesdirectedbyabureaucraticmanagementinwhichmanbecomesasmall,we
【招商银行】Itusedtobesostraightforward.Ateamofresearchersworkingtogetherinthelaboratorywouldsubmittheresultsofth
Couldthebadolddaysofeconomicdeclinebeabouttoreturn?SinceOPECagreedtosupply—cutsinMarch,thepriceofcrudeoilh
Couldthebadolddaysofeconomicdeclinebeabouttoreturn?SinceOPECagreedtosupply—cutsinMarch,thepriceofcrudeoilh
Asubsidiaryhasentered________apartnershiparrangementwithanothercompany.
MESBIC’saretheresltofthebeliefthatprovidingestablishedfirmswitheasieraccesstorelevantmanagementtechniquesandm
[2011年典型真题]America’smostpopularnewspaperwebsitetodayannouncedthattheeraoffreeonlinejournalismisdrawingtoaclose
Ifthepopulationoftheearthgoesonincreasingatitspresentrate,therewilleventuallynotbeenoughresourceslefttosus
随机试题
在中碳钢工件上,攻M10×1.5的内螺纹,求攻螺纹底孔的直径。
(2011年4月)_____是最早提出契约应适用当事人自主选择的法律的学者。
疖病常见于
A.血栓再通B.血栓机化C.血栓软化D.血栓钙化E.血栓栓塞血栓干燥收缩或部分溶解而出现裂隙,形成新的血管,并相互吻合沟通为
A.间期B.前期C.打击期D.处理期E.恢复期将可能受到影响的居民疏散到安全地方,保护即将受波及的设施属于突发公共卫生事件分期中的
食管癌病理分型,以下哪项是不正确的
什么是评定测量不确定度的GUM法?GUM法评定测量不确定度一般有哪些步骤?
根据《合同法》规定,要约可以撤回和撤销。下列要约,不得撤销的是:
个人独资企业,其生产经营所得实行核定应税所得率征收方式的,不能享受个人所得税的优惠政策。()
设函数f(x)有二阶连续导数,且f”(x)≠0,又有f(x+△x)=f(x)+△xf’(x+θ△x),0<θ<1.证明:
最新回复
(
0
)