∫0π/2x/(1+cosx)dx.

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问题0π/2x/(1+cosx)dx.

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答案0π/2x/(1+cosx)dx=∫0π/2x/2cos2x/2dx=∫0π/2xd(tanx/2)=xtanx/2|0π/2-∫0π/2tanx/2dx=π/2+2ln|cosx/2|0π/2=π/2-ln2.

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