A.C=K0(1-e-kt)/VK B.logC’=(-K/2.303)t’+log(K0/VK) C.logC’=(-K/2.303)t’+log(K0(1-e-KT)/VK) D.logC=(-K/2.303)t+logC0

admin2014-08-08  31

问题 A.C=K0(1-e-kt)/VK   
B.logC’=(-K/2.303)t’+log(K0/VK)   
C.logC’=(-K/2.303)t’+log(K0(1-e-KT)/VK)   
D.logC=(-K/2.303)t+logC0     
E.logX=(-K/2.303)t+logX0

选项 A、 
B、 
C、 
D、 
E、 

答案E

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