2. 考研
  3. 设y1，y2为dy/dx+P(x)y=Q(x)的两个特解，p，q为常数且py1-qy2为dy/dx+P(x)y=0的解，py1+qy2为dy/dx+P(x)y=Q(x)的解，则p=________，q=________．

设y1，y2为dy/dx+P(x)y=Q(x)的两个特解，p，q为常数且py1-qy2为dy/dx+P(x)y=0的解，py1+qy2为dy/dx+P(x)y=Q(x)的解，则p=________，q=________．

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问题 设y1，y2为dy/dx+P(x)y=Q(x)的两个特解，p，q为常数且py1-qy2为dy/dx+P(x)y=0的解，py1+qy2为dy/dx+P(x)y=Q(x)的解，则p=________，q=________．
选项
答案p=1/2，q=1/2
解析 由线性微分方程解的结构得p-q=0，P+q=1，解得p=1/2，q=1/2．
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考研数学二

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