2. 考研
  3. 设为曲面z=√(x2+y2)(1≤x2+y2≤4)下侧，f(x)为连续函数．计算I=[xy(xy)+2x-y]dydz+[yf(xy)+2y+x]dzdx+[zf(xy)+z]dxdy

设为曲面z=√(x2+y2)(1≤x2+y2≤4)下侧，f(x)为连续函数．计算I=[xy(xy)+2x-y]dydz+[yf(xy)+2y+x]dzdx+[zf(xy)+z]dxdy

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问题 设为曲面z=√(x2+y2)(1≤x2+y2≤4)下侧，f(x)为连续函数．计算I=[xy(xy)+2x-y]dydz+[yf(xy)+2y+x]dzdx+[zf(xy)+z]dxdy
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考研数学一

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