设f’(x)连续,f(0)=0,f’(0)≠0,F(x)=∫0xtf(t2-x2)dt,且当x→0时,F(x)~xn,求n及f’(0).

admin2018-05-21  23

问题 设f’(x)连续,f(0)=0,f’(0)≠0,F(x)=∫0xtf(t2-x2)dt,且当x→0时,F(x)~xn,求n及f’(0).

选项

答案F(x)=∫0xtf(t2-x2)dt=1/2∫0xf(t2-x2)d(t2-x2) [*] 则n-2=2,n=4,且 [*] =1/4f’(0)=1,于是f’(0)=-4.

解析
转载请注明原文地址:https://jikaoti.com/ti/RYVRFFFM
0

最新回复(0)