曲线ex+y-sin(xy)=e在点(0,1)处的切线方程为______.

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问题 曲线ex+y-sin(xy)=e在点(0,1)处的切线方程为______.

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答案[*]

解析 ex+y-sin(xy)=e两边对x求导得ex+y.(1+y’)-cos(xy).(y+xy’)=0,
将x=0,y=1代入得y’(0)=
故所求的切线方程为
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