设f’(x)=arcsin(x-1)2,f(0)=0,求∫01f(x)dx.

admin2018-11-11  22

问题 设f’(x)=arcsin(x-1)2,f(0)=0,求∫01f(x)dx.

选项

答案01f(x)dx=∫01f(x)d(x-1)=(x-1)f(x)|01-∫01(x-1)f’(x)dx =f(0)-∫01(x-1)f’(x)dx=-∫01(x-1)arcsin(x-1)2dx =[*]∫01arcsin(x-1)2d(x-1)2 [*]∫01arcsintdt=[*]∫01arcsintdt [*]

解析
转载请注明原文地址:https://jikaoti.com/ti/DnWRFFFM
0

最新回复(0)