设f(x,y)在全平面有连续偏导数,曲线积分∫Lf(x,y)dx+xcosydy在全平面与路径无关,且f(x,y)dx+xcosydy=t2,求f(x,y).

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问题 设f(x,y)在全平面有连续偏导数,曲线积分∫Lf(x,y)dx+xcosydy在全平面与路径无关,且f(x,y)dx+xcosydy=t2,求f(x,y).

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答案(1)∫Lf(x,y)dx+xcosydy在全平面与路径无关[*]积分得f(x,y)=siny+C(x). (2)求f(x,y)转化为求C(x). [*] f(x,y)=siny+2x-sinx2-2x2cosx2

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