∫02dy∫y2x2ex2dx=_________.

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问题02dy∫y2x2ex2dx=_________.

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答案[*]

解析 改变积分次序得
02dy∫y2x2ex2dx=∫02x2ex2dx∫0xdy=∫02x3ex2dx
=02x2ex2d(x3)04tetdt
=(t-1)et|=
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