设方程sin(x2+y2+z2)一xz=1确定函数z=z(x,y),求

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问题 设方程sin(x2+y2+z2)一xz=1确定函数z=z(x,y),求

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答案令F(x,y,z)=sin(x2+y2+z2)-xz一1,则 Fx=2xcos(x2+y2+z2)一z, Fy=2ycos(x2+y2+z2), Fz=2zcos(x2+y2+z2)一x, [*]

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