1由n/(n2+n)≤1/(n2+1)+1/(n2+2)+…+1/(n2+n)≤n/(n2+1)得n2/(n2+n)≤n(1/(n2+1)+1/(n2-2)+…1/(n2+n))≤n2/(n2+1)。由

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解析由n/(n²+n)≤1/(n²+1)+1/(n²+2)+…+1/(n²+n)≤n/(n²+1)得n²/(n²+n)≤n(1/(n²+1)+1/(n²-2)+…1/(n²+n))≤n²/(n²+1)。由

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考研数学二

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