The figure above shows 2 circles.The larger circle has center A,radius R cm.and is inscribed in a square.The smaller circle has

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问题
The figure above shows 2 circles.The larger circle has center A,radius R cm.and is inscribed in a square.The smaller circle has center C,radius r cm,and is tangent to the larger circle at point B and to the square at points D and F,If points A,B,C,and E are collinear,which of the following is equal to R/r?

选项 A、 
B、 
C、 
D、 
E、 

答案D

解析 Because is a diagonal of square CDEF, which has side length r, it follows from the Pythagorean an theorem that r2 + r2 = (CE)2, and hence CE = .
Therefore, BE= and AE = R + . Since 2(AE) is the diagonal length of the large square, which has side length 2R,it follows from the above tip that 2(AE) = (2R), or AE = R. Alternatively, an appropriate application of the Pythagorean theorem gives R2 + R2 = (AE)2, or AE = R.
Now substitute for AE and solve for R/r.

From the last equation we get
The correct answer is D.
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