连续函数f(x)满足f(x)=3∫0xf(x—t)dt+2,则f(x)=__________.

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问题 连续函数f(x)满足f(x)=3∫0xf(x—t)dt+2,则f(x)=__________.

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答案2e3x

解析=∫0xf(u)du得f(x)=3∫0xf(u)du+2,
  两边对x求导得f’(x)一3f(x)=0,解得f(x)一Ce—∫—3dx=Ce3x
  取x=0得f(0)=2,则C=2,故f(x)=2e3x
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