Sugarless yoghurt (酸奶) could help beat bad breath, tooth decay and gum disease, say scientists. Japanese researchers found eatin

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问题     Sugarless yoghurt (酸奶) could help beat bad breath, tooth decay and gum disease, say scientists. Japanese researchers found eating the yoghurt【C1】______levels of hydrogen sulphide (硫化氢) — a major【C2】______of bad breath — in 80% of volunteers. The【C3】______are active bacteria in yoghurt.
    Details were【C4】______at a meeting of the International Association for Dental Research. A(n)【C5】______of 24 volunteers who participated in the study were given strict instructions【C6】______oral health, diet and medicine taking. They spent two weeks【C7】______yoghurts and similar foods, like cheese. Researchers then【C8】______bacteria levels and odor-causing compounds,【C9】______hydrogen-sulphide. The volunteers then ate 90 grams of yoghurt a day for six weeks. At the end of the study, researchers took【C10】______again. They found hydrogen sulphide levels【C11】______in 80% of participants.
    Dr. Nigel Carter, chief executive of the British Dental Health Foundation, said, "The foundation has long been【C12】______people’s attention to sugar-free yoghurts as a healthy snack, so it is pleasing to hear that it may have oral health benefits we were previously【C13】______of."
    "Although this research is still in the early stages there is no【C14】______that sugar-free yoghurts provide a much healthier【C15】______to sweets and chocolate, and we would encourage snackers to【C16】______them into their diet."
    【C17】______, Dr. Carter stressed that the best way to beat bad breath was by【C18】______a good oral health routine. This involves brushing twice-a-day with fluoride (氟化物) toothpaste, cutting【C19】______on the frequency of sugary snacks and drinks and visiting a dentist【C20】______.
【C12】

选项 A、drawing
B、paying
C、attracting
D、concentrating

答案A

解析 语义衔接题。基金会的工作是把人们的注意力引导到无糖酸奶上,故答案为[A]drawing,drawing people’s attention to sth.。[B]paying的宾语只能是自己的注意力,不能是别人的;[C]attracting是要把注意力吸引到自己身上来,用在此处不合适;[D]concentrating与[B]同理排除。
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