设f(u)连续,则d2/dx2∫0xdu∫u1vf(u2-v2)dv=_______.

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问题 设f(u)连续,则d2/dx20xdu∫u1vf(u2-v2)dv=_______.

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答案-xf(x2-1)

解析u1vf(u2-v2)dv=-1/2∫u1f(u2-v2)d(u2-v2)f(t)dt,
则d/dx∫0xdu∫u1vf(u2-v2)dv=-1/2d/dx∫0xduf(t)dt,
d2/dx20xdu∫u1vf(u2-v2)dr=-xf(x2-1).
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