设函数y=y(x)由,确定,则y=y(x)在x=ln2处的法线方程为_____________.

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问题 设函数y=y(x)由,确定,则y=y(x)在x=ln2处的法线方程为_____________.

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答案[*](x-ln2)

解析 当x=ln2时,t=±1;当t=±1时,y=0.
(1)当t=-1时,由=-1,
du+arcsinudu=0两边对t求导得-2tarcsint2=0,
=-π,=兀,则法线方程为y=-(x-ln2).
(2)当t=1时,由
du+arcsinudu=0两边对t求导得-2tarcsint2=0,
=兀,=π,法线方程为y=-(x-ln2),
即法线方程为y=-(x-ln2).
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