首页
外语
计算机
考研
公务员
职业资格
财经
工程
司法
医学
专升本
自考
实用职业技能
登录
考研
Nearly all "speed reading" courses have a "pacing" element—some timing device which lets the student know how many words a minut
Nearly all "speed reading" courses have a "pacing" element—some timing device which lets the student know how many words a minut
admin
2012-02-02
32
问题
Nearly all "speed reading" courses have a "pacing" element—some timing device which lets the student know how many words a minute he is reading. You can do this simply by looking at your watch every 5 or 10 minutes and noting down the page number you have reached. Check the average number of words per page for the particular book you are reading. How do you know when 5 minutes has passed on your watch if you are busy reading the book? Well, this is difficult at first. A friend can help by timing you over a set period, or you can read within hearing distance of a public clock which strikes the quarter hours. Pace yourself every three or four days, always with the same kind of easy, general interest books. You should soon notice your accustomed w.p.m. rate creeping up.
Obviously there is little point in increasing your w.p.m. rate if you do not understand what you are reading. When you are consciously trying to increase your reading speed, stop after every chapter (if you are reading a novel) or every section or group of ten or twelve pages (if it is a textbook) and ask yourself a few questions about what you have been reading. If you find you have lost the thread of the story, or you cannot remember clearly the details of what was said, reread the section or chapter.
You can also try "lightning speed" exercise from time to time. Take four or five pages of the general interest book you happen to be reading and read them as fast as you possibly can. Do not bother about whether you understand or not. Now go back and read them at what you feel to be your "normal" w.p.m. rate, the rate at which you can comfortably understand. After a lightning speed reading through you will usually find that your "normal" speed has increased—perhaps by as much as 50-100 w.p.m. This is the technique sportsmen use when they usually run further in training than they will have to on the day of the big race. (341 words)
The purpose of the "lightning speed" exercise is to______.
选项
A、increase your speed by scanning the text first
B、test your maximum reading speed
C、help you understand more of the content of the book
D、enable you to win reading races against your friends
答案
A
解析
转载请注明原文地址:https://jikaoti.com/ti/QDbUFFFM
本试题收录于:
艺术硕士(艺术基础)题库专业硕士分类
0
艺术硕士(艺术基础)
专业硕士
相关试题推荐
Toomanyvulnerablechild-freeadultsarebeingruthlessly(无情的)manipulatedintoparenthoodbytheirparents,whothinkthatha
Toomanyvulnerablechild-freeadultsarebeingruthlessly(无情的)manipulatedintoparenthoodbytheirparents,whothinkthatha
Attentiontodetailissomethingeveryonecanandshoulddo—especiallyinatightjobmarket.BobCrossley,ahuman-resourcesex
Attentiontodetailissomethingeveryonecanandshoulddo—especiallyinatightjobmarket.BobCrossley,ahuman-resourcesex
ItcameassomethingofasurprisewhenDiana,PrincessofWales,madeatriptoAngolain1997,tosupporttheRedCross’scamp
Thefitnessmovementthatbeganinthelate1960sandearly1970scenteredaroundaerobicexercise(有氧操).Millionsofindividual
Sincewearesocialbeings,thequalityofourlivesdependsinlargemeasureonourinterpersonalrelationships.Onestrengtho
Sincewearesocialbeings,thequalityofourlivesdependsinlargemeasureonourinterpersonalrelationships.Onestrengtho
Britishuniversities,groaningundertheburdenofahugeincreaseinstudentnumbers,arewarningthatthetraditionofafree
Untilafewyearsagomostexpertsbelievedthatyoungchildrencouldn’tlieThelatedevelopmentalpsychologistJeanPiagetbel
随机试题
深度负反馈的闭环放大倍数与基本放大电路增益有关。
对葡萄糖重吸收的说明,正确的是
患者腹痛肠鸣,泻下粪便臭如败卵,但泻而不爽,脘腹胀满,舌苔白厚而腐,脉滑。治疗应首选()
当医院出现医院感染散发病例时,经治医师应填表报告医院感染管理科的时间是
A.普鲁卡因胺B.苯妥英钠C.利多卡因D.维拉帕米E.胺碘酮哪种药物若长期使用可引起红斑狼疮样症状()
( )是组织在其工作中直接形成的有保存价值的历史记录。
全淹没系统干粉灭火剂喷射时间一般不大于()s。
丙注册会计师完成了对C体育用品公司2009年度财务报表审计工作,并于2010年4月10日出具了审计报告,C公司的财务报表于4月15日公布。下列问题,请代为作出处理意见。2010年4月20日,丙注册会计师获知C公司在2009年3月20日出售了其在一家子公
你如何看待将“见危不救”入罪?
设函数f(u)连续,区域D={(x,y)|x2+y2≤2y},则f(xy)dxdy等于()
最新回复
(
0
)