设f’(x)在[0,1]上连续,且f(1)一f(0)=1.证明:∫01f’2(x)dx≥1.

admin2015-07-10  31

问题 设f’(x)在[0,1]上连续,且f(1)一f(0)=1.证明:∫01f’2(x)dx≥1.

选项

答案由1=f(1)一f(0)=∫01f’(x)dx, 得12=1=(∫01f’(x)dx)2≤∫0112dx∫01f’2(x)dx=∫01f’2(x)dx,即∫01f’2(x)dx≥1.

解析
转载请注明原文地址:https://jikaoti.com/ti/LtNRFFFM
0

相关试题推荐
最新回复(0)