设f(u,v)一阶连续可偏导,f(tx,ty)=t3f(x,y),且f′1(1,2)=1,f′2(1,2)=4.则f(1,2)=________.

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问题 设f(u,v)一阶连续可偏导,f(tx,ty)=t3f(x,y),且f′1(1,2)=1,f′2(1,2)=4.则f(1,2)=________.

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答案3

解析 f(tx,ty)=t3f(x,y)两边对t求导得
xf′1(tx,ty)+yf′2(tx,ty)=3t2f(x,y),
取t=1,x=1,y=2得f′1(1,2)+2f′2(1,2)=3f(1,2),故f(1,2)=3.
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