设f(χ,y),可微,f′χ(χ,y),f(0,)=1,且满足=ecoty,求f(χ,y).

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问题 设f(χ,y),可微,f′χ(χ,y),f(0,)=1,且满足=ecoty,求f(χ,y).

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答案[*] 两边对y积分lnf(0,y)=lnsiny+lnc, f(0,y)=csiny而f(0,[*])=1[*]C=1, f(0,y)=siny, [*]=-1[*]lnf(χ,y)=χ+lnC1(y), f(χ,y)=C1(y)e, f(0,y)=C1(y)=siny, 所以f(χ,y)=sinye

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