当|y|≤1时,F(y)=∫-11|x—y|exdx,则F’(0)=[ ].

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问题 当|y|≤1时,F(y)=∫-11|x—y|exdx,则F’(0)=[    ].

选项 A、一2一e—e-1
B、2一e—e-1
C、2+e-e-1
D、2+e+e-1

答案B

解析   F(y)=∫-1y|x—y|exdx
                =∫-1y(y-x)exdx+∫y1(x-y)exdx
                =y∫-1yexdx一∫-1yxexdx+∫y1xexdx-y∫y1exdx,

    F’(y)=∫-1yexdx+yey—yey—yey—∫y1exdx+yey
          =∫-1yexdx一∫y1exdx,
    F’(0)=∫-10exdx一∫01exdx
    =ex-10一ex01=2一e—e-1
故选(B).
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